Geos 306, Fall 2001, Lecture 12
Mineralogy of the Earth's Crust
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When examining the mineralogy of the Earth's crust we find that there are
two mineral groups that are more abundant, and therefore more important,
than any of the other mineral groups: silica and feldspars.
These two groups will be the subject of today's lecture.
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The Earth's crust consists of ~12% silica and 50-60% feldspar, by molar
abundances.
Silica, SiO2
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The major phases of silica include quartz, cristobalite, tridymite, coesite,
and stishovite, but there are about 50 different phases currently known.
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Examine the silica phase diagram.
quartz

cristobalite

tridymite

coesite
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The most studied mineral is quartz because it is the prototype for our
understanding of all the silicates.
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Framework, CN(Si)=4. CN(O)=2. Pauling’s rules.
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With application of pressure it adopts a more uniform packing arrangement,
then it turns to glass around 25 GPa
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With application of temperature it undergoes a displacive transformation
to the hexagonal b form.
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Weathering mechanism, true for all types of weathering. H attaches to an
O atom, then the other bonds lengthen, then break.
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Useful as a source of Si and for silica. It is used in electronics as an
oscillator, e.g. quartz watches.
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The structure is made out pf helixes of tetrahedra that wind parallel to
the c-axis. It was once thought that the first DNA molecule grew on the
surface of a quartz crystal, using these helixes as a template. We now
know that this is not true, because the size of the quartz helix is too
small. Some scientists now believe that the structure of clay offers a
perfect size template for growing DNA.
Feldspars
Albite NaAlSi3O8
K-spar KAlSi3O8
Anorthite CaAl2Si2O8

high albite (high temperature form, disordered Si/Al)
low albite (ordered Al/Si)
Microcline (ordered Al/Si)
Orthoclase (partially ordered Al/Si)
Sanidine (disordered Al/Si)
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Channels are large in the feldspars so diffusion is rapid and easy.
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Movie showing compression
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Weathering related to H bonding to bridging O atoms, just as for quartz
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Sizes of cations: r(K)> r(Na)=r(Ca) means no substitution of K for Na or
Ca
but Ca and Na substitute if we have the coupled substitution of CaAl
for NaSi.
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Plagioclase, alkali solid solutions
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Na-K feldspar exsolution